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The kinematic equations

What you'll learn

Derive the constant-acceleration equations from one picture: the area under a straight v–t line.

Most textbooks hand you the kinematic equations as a list to memorize. You're going to read them off a picture instead — because when acceleration is constant, the v–t graph is a straight line, and everything about straight lines is easy.

The setup

Constant acceleration a, starting velocity v₀. The velocity line is:

v=v0+atv = v_0 + at

That's not a new fact — it's just "slope × run": start at v₀ and add a for every second. First equation done.

Displacement is the area

How far did you go by time t? The area under the velocity line — and that area splits into two friendly shapes:

tvv₀ · t½ a t²v₀vt
Displacement is the whole area: the rectangle you'd cover coasting at v₀ plus the triangle the acceleration adds. Read the areas and x = v₀t + ½at² writes itself.

The rectangle is the distance you'd cover just coasting at v₀. The triangle — base t, height at — is the extra distance the acceleration adds:

x=v0t+12at2x = v_0 t + \tfrac{1}{2} a t^2

The famous ½ isn't mysterious. It's the area of a triangle.

The shortcut without time

Sometimes you know speeds and distance but not the time ("how long a runway does a plane need to reach takeoff speed?"). Solve v = v₀ + at for t, plug it into the area formula, and t cancels:

v2=v02+2aΔxv^2 = v_0^2 + 2a\,\Delta x

Worth checking the algebra once by hand — after that, it's yours.

The toolkit

EquationUse it when
v = v₀ + atyou don't care about distance
x = v₀t + ½at²you don't know the final velocity
v² = v₀² + 2aΔxyou don't know the time

Three equations, one straight line, zero memorization: the first is the line's slope, the second is the area under it, the third is the two combined with t eliminated.

Why this matters

Constant acceleration isn't a toy case — it's gravity. Everything in the next module (free fall, projectiles) is these three equations with a = g pointed down.

Check your understanding

Question 1 of 2

In x = v₀t + ½at², where does the ½ come from?

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