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The derivative as a function

What you'll learn

Read f′(x) as its own function: positive where f rises, negative where it falls, zero at the turns.

The derivative f′(x) isn't a single number — it's a new function. Feed it any x and it returns the slope of f there. Seeing f′ as a function of its own is the shift that makes the rest of calculus click.

f and f′, side by side

ff′f′ < 0 (f falling)f′ > 0
The derivative is a function in its own right. Where f rises, f′ sits above zero; where f falls, f′ dips below; at each turn of f, f′ crosses zero.

Read the two graphs together and the link is exact:

  • Where f is rising, its slope is positive, so f′ sits above its axis.
  • Where f is falling, its slope is negative, so f′ sits below.
  • At each turning point of f, the slope is momentarily zero, so f′ crosses zero.

The bottom curve is just the top curve's slope, plotted point by point.

Notation

The same idea wears several notations — get comfortable with all of them:

NotationRead asStyle
f′(x)"f prime of x"Lagrange
dy/dx"dee y dee x"Leibniz
d/dx [ f(x) ]"d by dx of f"Leibniz (operator)

Leibniz's dy/dx deliberately echoes the rise-over-run "Δy/Δx" of a slope — it remembers where the derivative came from.

Higher derivatives

Differentiate f′ and you get the second derivative, f″ — the rate at which the slope itself is changing. Position → velocity (f′) → acceleration (f″) is the classic chain. We'll put f″ to work on concavity soon.

Why this matters

Treating f′ as a function is what lets calculus answer questions about a whole curve at once: where it's steepest, where it levels off, where it turns. You stop computing one slope at a time and start reasoning about the slope everywhere.

Check your understanding

Question 1 of 2

Where f is decreasing, its derivative f′ is:

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