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Increasing, decreasing, and extrema

What you'll learn

Use the sign of f′ to find where a function rises, falls, and reaches its local maxima and minima.

The derivative tells you the slope — and the slope tells you the shape. The sign of f′ alone reveals where a function climbs, where it descends, and where it peaks or bottoms out.

Sign of f′ = direction of f

local maxf′ = 0local minf′ = 0f′ > 0f′ < 0f′ > 0
Read the sign of f′ across each interval: positive means rising, negative means falling. Where f′ flips + to −, you’ve found a local max; − to +, a local min.

The rule is simple and exact:

  • f′(x) > 0 on an interval → f is increasing there.
  • f′(x) < 0 → f is decreasing.
  • f′(x) = 0 → the tangent is flat: a critical point, a candidate for a peak or valley.

The first-derivative test

Critical points are only candidates. To classify one, look at how f′ changes sign as you pass through it:

f′ changesat the critical point
+ then −local maximum
− then +local minimum
no sign changeneither (a plateau or a saddle-like flat)

It matches intuition: a peak is where the curve stops climbing and starts falling, so its slope goes from positive to negative.

Finding them, step by step

For f(x) = ½x³ − ⁠1.5x:

  1. Differentiate: f′(x) = 1.5x² − 1.5.
  2. Set to zero: 1.5x² − 1.5 = 0 → x² = 1 → x = ±1 (the critical points).
  3. Test signs: f′ is positive for x < −1, negative between −1 and 1, positive for x > 1. So x = −1 is a local max (+ to −) and x = 1 is a local min (− to +).

Why this matters

This is how you find the best and worst points of anything a function models — peak power, minimum drag, highest profit — without plotting the whole graph. Set the derivative to zero, then read the sign changes.

Check your understanding

Question 1 of 2

If f′(x) > 0 on an interval, then on that interval f is:

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