The Pythagorean identity
What you'll learn
See why sin²θ + cos²θ = 1 falls straight out of the unit circle — the identity every other one is built on.
The trigonometry course showed where sin and cos come from. Pre-calculus puts them to work as functions you can manipulate — and that starts with the one identity everything else is built on.
It's just Pythagoras on the unit circle
Place a point P on the unit circle at angle θ. By definition, its coordinates are (cos θ, sin θ). Drop a vertical line and you've made a right triangle:
- the horizontal leg has length cos θ
- the vertical leg has length sin θ
- the hypotenuse is the radius, length 1
The Pythagorean theorem (leg² + leg² = hyp²) reads, on this triangle:
sin²θ + cos²θ = 1
That's the Pythagorean identity. It isn't a new fact to memorize — it's the oldest theorem in geometry, applied to a triangle of radius 1. (Note the shorthand: sin²θ means (sin θ)².)
The two it generates
Divide the whole identity by cos²θ, and again by sin²θ, and two more identities drop out for free:
| Divide by | Result |
|---|---|
| cos²θ | tan²θ + 1 = sec²θ |
| sin²θ | 1 + cot²θ = csc²θ |
So the single circle relation seeds all three Pythagorean identities.
What identities are for
An identity is true for every angle, which makes it a legal swap you can make anywhere. Their main job is to rewrite an expression into a form you can actually work with:
- Simplify: 1 − sin²θ is just cos²θ.
- Solve equations: replace sin²θ with 1 − cos²θ so everything is in one function.
Why this matters
The Pythagorean identity is the most-used line in all of trigonometry. In calculus it's the key that unlocks integrals full of sines and cosines — you swap sin²θ for 1 − cos²θ (or use sec²θ = tan²θ + 1) to turn an impossible-looking integral into a routine one.
Check your understanding
Question 1 of 2
If cos θ = 0.6 and θ is in the first quadrant, what is sin θ?