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Rational functions and asymptotes

What you'll learn

Find the vertical and horizontal asymptotes that a rational function approaches but never crosses.

A rational function is one polynomial divided by another, like f(x) = 1 / (x − 1). Dividing introduces something new: lines the graph rushes toward but never touches — asymptotes.

Vertical asymptotes: where the bottom hits zero

A fraction blows up when its denominator approaches zero. So wherever the bottom equals zero (and the top doesn't), the function shoots off to ±∞:

x = 1y = 0
The curve dives toward the lines but never touches them: x = 1 is forbidden (it makes the bottom 0), and y = 0 is the value it heads to far out.

For f(x) = 1 / (x − 1), the denominator is zero at x = 1. That input is banned from the domain, and the graph hugs the vertical line x = 1 without ever crossing it.

Horizontal asymptotes: where the graph heads far out

Push x toward ±∞ and ask what height the graph settles at. Compare the degrees of top and bottom:

Top vs. bottom degreeHorizontal asymptote
top degree smallery = 0
degrees equaly = ratio of leading coefficients
top degree largernone (it grows without bound)

For 1 / (x − 1), the top (degree 0) is smaller than the bottom (degree 1), so the horizontal asymptote is y = 0 — far out in either direction, the curve flattens toward the x-axis.

A subtlety: holes vs. asymptotes

If a factor cancels from top and bottom, you get a hole, not an asymptote. For (x − 2)/((x − 2)(x + 1)), the (x − 2) cancels: there's a hole at x = 2 and a true vertical asymptote only at x = −1. Always factor first.

Why this matters

Asymptotes describe limits in disguise — "approaches but never reaches" is the language of the final module. They also model the real world: a drug's concentration decaying toward zero, or a population leveling off at the carrying capacity its environment can support.

Check your understanding

Question 1 of 2

Where is the vertical asymptote of f(x) = 1 / (x + 2)?

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